# Calculation Example

### Step 1: Calculate the Area of the Property

This is what a typical home landscape map may look like: A.) Break the property into easily measurable pieces. Determine the area of each of those pieces.

Large rectangle:

67' X 130' = 8,710 ft2

From the formula: Area of a square/rectangle = Length X Width

Triangle:

130' - 85' = 45' and then 45' - 25' = 20' (Leg 1)

87' - 67' = 20' (Leg 2)

Where Leg 1 runs parallel to the 130' line and Leg 2 runs perpendicular to Leg 1

1/2 (20' X 20') =1/2 (400') = 200 ft2

From the formula: Area of a triangle =1/2 Base X Height

Small "Square":

20' X 25' = 500 ft2

From the formula: Area of a square/rectangle = Length X Width

8,710 ft2 + 200ft2 + 500 ft2 = 9,410 ft2

This is the total area of the property.

However, a typical landscape may actually look like this:

### Step 2: Calculate the Area of All Areas Not Covered by Lawn

A.) Measure the area (Length X Width) of all spaces not covered by lawn:

See column one and two of table.

See column three of table.

### Step 3: Figure the Area of Lawn to be Covered With Fertilizer

Subtract the area of the property from the area not to be covered by lawn:

 Property Area = 9,410.0 ft2 Area Not Covered by Lawn = -4,857.5 ft2

9,410.0 ft2 - 4,857.5 ft2 = 4,552.5 ft2

Therefore, there are 4,550 square feet of lawn to fertilize. Note that 4,552,5 ft2 was rounded off to a slightly lower number. The University of Maryland recommendation for a lawn fertilizer application is 0.9 pounds of NITROGEN per 1,000 square feet per application. This means that not more than 0.9 pounds of actual nitrogen should be applied during any one application. Most cool season grasses only need 1.8 pounds of Nitrogen per year. Most lawns are not exactly 1,000 square feet. Since all University of Maryland recommendations are based on per 1,000 square feet, a conversion factor is needed. This conversion factor is already built into the formula below.

### Step 4: Calculate the Amount of Fertilizer Needed

So the question is: How much fertilizer is needed to maintain this lawn? In relation to the University's recommendations, the question should be: How much Nitrogen is needed to maintain this lawn? A more specific way to pose the question would be: How much fertilizer is needed to add 9/10 or 0.9 pounds of actual Nitrogen to the lawn?

 Lawn size = 4,550 ft2 Fertilizer Formulation = 30-0-12 Application rate = 0.9 pounds of actual Nitrogen per 1000 ft2

From the formula:

Total Fertilizer Needed = N Application rate in lb per 1,000 ft2/N content of fertilizer as a decimal X Lawn size in ft2/1,000

Solve:

0.9/.30 X 4,550/1,000 = 3 X 4.55 = 13.65

So, 13.65 pounds of 30-0-12 fertilizer is needed to make one application to the 4,550 ft2 lawn.

Note: Most bags of lawn fertilizer contain enough product to cover 5,000 or 15,000 ft2 of area. Read the label to determine this.